Hello,
If a rectangular waveguide (or square well, etc) is centered at x=a/2, y=b/2, solution (e.g. for TE mode) is:
H = Ho Cos(m*pi*x/a) * Cos(n*pi*y/b) (n,m = 0,1,2,...)
So for TEn=0,m=1, H = Ho Cos(pi*x/a).
If it is centered at the origin, you get even and odd solutions:
H = Ho Cos(m*pi*x/2a) * Cos(n*pi*y/2b) (n,m odd)
H = Ho Sin(m*pi*x/2a) * Sin(n*pi*y/2b) (n,m even).
Now, what is the corresponding values for n,m that give the same mode?
If a rectangular waveguide (or square well, etc) is centered at x=a/2, y=b/2, solution (e.g. for TE mode) is:
H = Ho Cos(m*pi*x/a) * Cos(n*pi*y/b) (n,m = 0,1,2,...)
So for TEn=0,m=1, H = Ho Cos(pi*x/a).
If it is centered at the origin, you get even and odd solutions:
H = Ho Cos(m*pi*x/2a) * Cos(n*pi*y/2b) (n,m odd)
H = Ho Sin(m*pi*x/2a) * Sin(n*pi*y/2b) (n,m even).
Now, what is the corresponding values for n,m that give the same mode?