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falling under gravity with decreasing r

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If you drop an object from a great height with no air resistance. e.g. 1000 km above the moon. How long will it take to hit the surface?

(GM[itex]_{}1[/itex]M[itex]_{}2[/itex])/r[itex]^{}2[/itex] = M[itex]_{}2[/itex]a

r[itex]^{}..[/itex]=k/r[itex]^{}2[/itex]

Hmm this is my first post, not quite getting the symbols.

"The second derivative of r is equal to a constant divided by r squared"

So presumably you integrate that nonlinear differential equation. Somehow.

This is quite an obvious question. It seems like something Isaac Newton would have asked when he first discovered the equations of gravity. A really classic piece of physics. But I can't seem to calculate the answer or find it anywhere.

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