the electric displacement vector field and Gauss' law?

Hi,

I know that for the electric displacement vector field [itex]\oint D.dS[/itex]=[itex]\sum Q_{c}[/itex] does this mean that I can just use a Gaussian surface to explain why the displacement vector field for a sphere is radial or not without having to talk about the electric field. If not what is the reasoning to explain that the displacement vector field is radial? or is there just a definition for which direction the displacement field always points in.

Thanks.