Guy, i have a problem. When we use conservation energy to find the escape velocity, ie the root of potentiality is unlimited, why we don't compute the velocity of earth? We knew the earth rotated its axis, then everything in surface was had linear velocity. So when we launch a thing, it's general velocity is sum of 2 vector velocity, one is linear velocity, other is velocity we supplied. That is
(0.5 ×mv^2) +(0.5×mV^2)-(GMm÷(r^2))>=0
Which v,V are linear velocity and velocity of thing we launched respectively
We obtain,..........
(0.5 ×mv^2) +(0.5×mV^2)-(GMm÷(r^2))>=0
Which v,V are linear velocity and velocity of thing we launched respectively
We obtain,..........