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Tangential acceleration in circular motion

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We know that the magnitude of tangential component of acceleration is,
atangential = dv/dt (where v is speed)
So clearly atan = 0 for uniform circular motion (as v is constant)

But what about non-uniform circular motion?
I can see atan = 0 only when v = constant. But in non uniform circular motion v is not constant.
Does it mean that atan can never be zero if the particle is moving in non-uniform circular motion?
(It never seems to be the case.)
Would someone please explain?

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