how much stuff will neutralise the sun's pull on the earth

I tried to make the title as descriptive as I could without being overly long.

Anyway, I've been trying to work this out but I'm having some difficulty. We all know the strength of the electromagnetic force is very much greater than the gravitational force. I'm not sure what it is as it's a number that seems to vary between 10^35 and 10^40 times depending on the source. And the mass of the earth is 6 x 10^24kg.

For the sake of the argument, let's call the gravitational force 10^36 times weaker than the EM force and the mass of the earth as 10^25kg

I was trying to work out given the above numbers, how many kg's of protons would need to be evenly spread through the sun and also evenly spread through the earth, such that the electromagnetic repulsion would be enough to overcome the pull of the gravitational attraction between the two objects (sun and earth) So that the earth would float away.

At first I thought it would be simple to work out but after thinking about it for a while I realise that I don't really know how to do this.

I hope this makes sense.