ds/dt and dr/dt

This is one very basic question. But I just need to confirm if I understood it right.

Suppose a particle moves along a curve and crosses Δs path in Δt time. Then we can say the velocity of the particle is [itex]\vec{v}[/itex] = ds/dt [itex]\hat{u}[/itex]
Where [itex]\hat{u}[/itex] is tangent to the curve.

Also if the same particle, as it crosses Δs, goes through a displacement Δ[itex]\vec{r}[/itex] in the same time interval Δt we say [itex]\vec{v}[/itex] = d[itex]\vec{r}[/itex]/dt

Is the V's calculated above are same (ie equal)?

I know the question is silly, but at present this forum is the only place for me to get help.