So I derived this equation for the net force/acceleration of a motorcycle on a flat surface. I beleive this equation could practically be used for any rolling object.
ƩF = Fp - μ*Fn - FD
Where: FP is the force of the bike acting against the ground, tangent to the ground
FD = [itex]\frac{1}{2}[/itex]pv2CDA (air drag)
μ*Fn is the frictional force of the tires, Fn is the normal force.
Now to find a:
ma = Fp - μFn - FD
a = (Fp - μFn - FD) / m
Is there anything wrong with this?
ƩF = Fp - μ*Fn - FD
Where: FP is the force of the bike acting against the ground, tangent to the ground
FD = [itex]\frac{1}{2}[/itex]pv2CDA (air drag)
μ*Fn is the frictional force of the tires, Fn is the normal force.
Now to find a:
ma = Fp - μFn - FD
a = (Fp - μFn - FD) / m
Is there anything wrong with this?