how can rcosθ in a banked road be equal to mg; since r is equal to normal reaction which is equal to mgcosθ. rcos is even smaller than r.
so
mg>mgcosθ
mgcosθ=r
r>rcosθ
so
mg>rcosθ
then how can mg=rcos when banking in curved road?
so
mg>mgcosθ
mgcosθ=r
r>rcosθ
so
mg>rcosθ
then how can mg=rcos when banking in curved road?